X^2+25x-5100=0

Solution for X^2+25x-5100=0 equation:

X^2+25X-5100=0

a = 1; b = 25; c = -5100;
Δ = b2-4ac
Δ = 252-4·1·(-5100)
Δ = 21025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{21025}=145$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-145}{2*1}=\frac{-170}{2}
=-85
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+145}{2*1}=\frac{120}{2}
=60
$